Solved Sort command output by a numerical column

[damix9]

I have a script https://www.linux.org/threads/linux-org-user-created-helpful-shell-scripts.41234/post-249595
It outputs multiple lines, each line has some space-separated values. How to sort the output by 6th value? Treat it as a real number.

./kt.sh info | sort -n -k 6

sorts in some random order.
For the output format see line 100 of the script

...
printf "%3.0lf%% of %11d %4.0lf kb/s %s %8s %4s %s \n" $((100*$prog/$dsize)) $dsize $(($speed/1000)) $(echo "scale=5 ; $ratio / ($seed_time / 24)" | bc -l | awk '{printf "%.5f\n", $0}') $sl $pri "$name"
...

UPD
Solution

 

[damix9]

UPD

I found a dirty workaround

./kt.sh info | sed 's/\./,/g' | sort -n -k 6

sorts as expected, but replaces dots with commas in all the output.
There's an answer on https://unix.stackexchange.com/questions/459257/how-to-sort-lines-by-float-number

my locale uses a comma as decimal separator, so I had to use LC_NUMERIC=C sort

It's also a thing for me. How to alter my one-liner to use dot as decimal separator when sorting?

 

[damix9]

I found a working one-liner

./kt.sh info | LC_NUMERIC=C sort -n -k 6